5
4
3
2
1
0
−1
−2
−3
−4
−5
x
y
−5
−3
−1
0
1
2
3
4
5
Trace at:
x=
y=2
1(2x23x2)
a=

Factoring ax2+bx+c

In the previous lesson, you learned how to factor polynomials of the form x2+bx+c, and how to use that to solve equations that look like x2+bx+c=0. In this lesson, you will learn how to do the same thing with quadratic polynomials where the x2 term could have a coefficient different from 1.


Factoring out a constant

Question 1 of 13. The equation y=a(2x23x2) is graphed on the grid to the left, with a slider for a.

When a is set to 1, the graph has two x-intercepts, one where x is positive and one where x is negative. Give the positive one. (,0)
Give the positive x-intercept of the graph when a is set to 2. (,)
Does setting a to any nonzero value affect the x-intercepts of the graph?
Does setting a=0 affect the x-intercepts of the graph?
What is a positive solution to the equation 3(2x23x2)=0? x=
What is a positive solution to the equation 20(2x23x2)=0? x=
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